Show That B 2 C 2 Ab Ac Ba C 2 A 2 Ca Cb A 2 B 2 4a 2b 2c 2
A² b² c² = (abc)² 2 (ab bc ca) The actual formula is (abc)² = a² b² c² 2 ( ab bc ca) You can get this simple formula by multiplying (ab c) with (abc) (ab c)² = (ab c)* (ab c) = a* (ab c) b* (ab c) c* (ab c) = a² ab ac ab b² bc ca bc c² = a² b² c² 2ab 2bc 2caRecall the formula `(abc)^2 = a^2 b^2 c^2 2(ab bc ca)` Given that `a^2 b^2 c^2 = 250 , ab bc ca = 3 ` Then we have `(abc)^2 = a^2 b^2 c^2 2 (ab bcca)` `(abc)^2 = 250 2(3)` `(abc)^2 = 256` `(abc) =± 16` ⇒ v = 2ab 2ca 2bc ⇒ 2ab 2ca = v− 2bc (abc) (a^2b^2c^2abbcca)=a^3b^3c^33abc and problems on it If playback doesn't begin
